Rewrite the quadratic function in vertex form.
y=3x^2-12x+4

vertex form is y=a(x−h)2+k. To solve this you have to complete the square with the x terms: y= 3x2−12x+4. first isolate the x terms: y−4=3x2−12x. ax2+bx+c to complete the square a=1 and c=(12b)2.

Step-by-step explanation:

vertex form is y=a(x−h)2+k. To solve this you have to complete the square with the x terms: y= 3x2−12x+4. first isolate the x terms: y−4=3x2−12x. ax2+bx+c to complete the square a=1 and c=(12b)2.

Find a common denominator on the right side of the equation

Step-by-step explanation:

The equation before the problem is

X² + b/a(x) + (b/2a)²= -c/a + b²/4a²

The next step in solving the above equation is to fibd tge common denominator on the right side of the equation.

X² + b/a(x) + (b/2a)²= -c/a + b²/4a²

X² + b/a(x) + (b/2a)²= -4ac/4a² + b²/4a²

X² + b/a(x) + (b/2a)²=( b²-4ac)/4a²

The right side of the equation now has a common denominator

The next step is to factorize the left side of the equation.

(X+b/2a)²= ( b²-4ac)/4a²

Squaring both sides

X+b/2a= √(b²-4ac)/√4a²

Final equation

X=( -b+√(b²-4ac))/2a

Or

X=( -b-√(b²-4ac))/2a