Mathematics: Round to nearest tenth if needed find the measure of y

Round to nearest tenth if needed find the measure

maryanapritchak1829

06.01.2022

$\large\boxed{y=3\sqrt5\approx6.7}$

Step-by-step explanation:

ΔABC and ΔDAC are similar. Therefore the corresponding sides are in proportion:

$\dfrac{AC}{BC}=\dfrac{DC}{AC}$

We have

$AC=y\\BC=3+12=15\\DC=3$

Substitute:

$\dfrac{y}{15}=\dfrac{3}{y}$ cross multiply

$y^2=(15)(3)\\\\y^2=45\to y=\sqrt{45}\\\\y=\sqrt{9\cdot5}\\\\y=\sqrt9\cdot\sqrt5\\\\y=3\sqrt5\\\\y\approx6.7$

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veronica022

06.03.2020

x = 1, y = 2

Step-by-step explanation:

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