Ryan bought a bike for $47,000 in the year 2002. Its value depreciates by 2% per year. What is the value of the bike in 2006?

A. $19,251
B. $37,600
C. $43,351
D. $50,874

help me pls:/

We need to locate the median of the set given. So, it's important for us to arrange the data in increasing order first. Hence we have

10.5 11 11.5 14.5 14.5 17 17 18 19 
 
Now that we have the value of the median for  the entire set, we now separate the group into a group below and above the median as shown below.

(10.5 11 11.5 14.5) 14.5 (17 17 18 19)

Now, let's find the median for the subgroup. For the lower boundary, the media is (11 + 11.5)/2 = 11.25. As for the upper boundary, we have (17 + 18)/2 = 17.5. 

The interquartile range (IQR) is the difference between the two medians of the lower and upper boundary. Hence, the IQR = 17.5 - 11.25 = 6.25.

6.25