jessied2000
07.07.2019 •
Mathematics
Sal currently has an account balance of $2,835.48. he opened the account five years ago with a deposit of $2310.72. if the interest compounds twice a year, what is the interest rate on the account?
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Ответ:
A=p (1+r/k)^kt
A future value 2835.48
P present value 2310.72
R interest rate?
K compounded twice a year 2
T time 5 years
Solve the formula for R
R= [(A/p)^(1/kt)-1]×k
R=((2,835.48÷2,310.72)^(1÷10)−1)×2
R=0.0414×100
R=4.14%
Hope it helps!
Ответ:
-15
Step-by-step explanation:
First combine like terms, aka the variables
-5n+4n-7=8
-1n-7=8
Then, isolate the variable by adding 7 to both sides
-1n-7+7=8+7
-1n=15
Finally, solve by dividing both sides by -1
-1n/-1=15/-1
n=-15