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zappygal923
12.07.2019 •
Mathematics
Saline solution a is 10% strength and saline solution b is 5% strength. i have an order for 6 litres of an 8% saline solution. to fill the order how many litres of solution a should be diluted with solution b? (hint. assume a 1% solution contains r grams of salt per litre.)
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Ответ:
y = volume of saline solution B.
We're going to set up two equations.
Firstly, x + y = 6. That gives us y = 6 – x (1)
Second, 0.1x + 0.05y = 0.08•6,
or 0.1x + 0.05y = 0.48 (2)
Substitute (1) into (2):
0.1x + 0.05(6 – x) = 0.48
0.1x + 0.3 – 0.05x = 0.48
0.05x + 0.3 = 0.48
Subtract 0.3 from both sides:
0.05x = 0.18
x = 3.6
Then y = 6 – 3.6 = 2.4
So we have to use 3.6 litres of solution A and 2.4 litres of solution B.
Ответ:
Ответ:
im dumb i can even do my own work :)