Sally is given the information ƒ(1)= 0, ƒ(-2)=0 and ƒ(3)=0. which are the factors of the polynomial?

F(1) = 0 tells you that wherever you see an x, you put in a one. When you do, the answer comes out as 0

So one of he factors for f(x) is
f(x) = (x -1) * g(x) 
If you put an 1 into (x - 1) you get (1 - 1) = 0
The whole thing goes to zero when that happens.

If you split up g(x) so that when x = - 2, the whole polynomial goes to 0 just as what happened with x = 1

f(x) = (x - 1) (x + 2) * h(x)

When x = 3 the same thing happens.
f(x) = (x - 1)(x + 2)(x - 3) and that's your complete answer.

43.1N

Step-by-step explanation:

this question involves the application of the use of the equations of motion and the newton's law of motion

the parameters are

initial velocity u = 0

distance (s)= 12

mass (m)=5.5kg

t=1.75s

a= acceleration

S= ut + at²

12= (0×1.75) + ( × a × 1.75²)

12= 0 + (1.53125 × a)

12 = 1.53125 × a

a = 12÷1.53125

a= 7.8367m/s²

F=m × a

=5.5 × 7.8367

=43.10N