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gjeaneasley
24.11.2019 •
Mathematics
Select all the points that are on the graph of the line 2x + 4y=20 .5) b. (0,10) c. (1,2) d.) (1,4) e.) (5,0) f. (10,0)
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Ответ:
The points a. (0,5) and f. (10,0) will lie on the given line.
Step-by-step explanation:
The given equation of line is
.
Now, it is required to check whether the given point lie on the line or not. To check it, put the points in the equation of line and if they satisfies, then the point will be on the line else not.
(a) The first point is (0,5). Put this point in the equation as,
Thus, the point satisfies and it will lie on the line.
(b) The first point is (0,10). Put this point in the equation as,
Thus, the point doesn't satisfy and hence, it will not lie on the line.
(c) The first point is (1,4). Put this point in the equation as,
Thus, the point doesn't satisfy and hence, it will not lie on the line.
(d) The first point is (5,0). Put this point in the equation as,
Thus, the point doesn't satisfy and hence, it will not lie on the line.
(f) The first point is (10,0). Put this point in the equation as,
Thus, the point satisfies and it will lie on the line.
Therefore, points (0,5) and (10,0) will lie on the given line.
Refer the graph of line and points.
For more details, refer the link:
link
Ответ:
(0,5) and (10,0)
Step-by-step explanation:
The equation of the straight line is given by 2x + 4y = 20 .......... (1)
Now, point (0,5) satisfies the equation (1) as putting x = 0, we will get y = 5.
Now, point (0,10) does not satisfy the equation (1) as putiing x = 0, we get y = 5 ≠ 10
Again, point (1,2) does not satisfy the equation (1) as putiing x = 1, we get y = 4.5 ≠ 2
Now, point (1,4) does not satisfy the equation (1) as putiing x = 1, we get y = 4.5 ≠ 4
Again, point (5,0) does not satisfy the equation (1) as putiing y = 0, we get x = 10 ≠ 5
Finally, point (10,0) satisfies the equation (1) as putiing y = 0, we get x = 10 .
Therefore, only points (0,5) and (10,0) are on the graph of the line 2x + 4y = 20 (Answer)
Ответ:
15 days:)
Step-by-step explanation: