Select the vertical asymptote(s) of the function

A. x=2
B. x=-6
C. x=2, x=-6
D. x=-2

As the described function, we want to find vertical asymtotes, we find the value of x so that the denominator is equal to 0.

Here, (x - 2)(x + 6) = 0

=> x = 2, x =-6

=> Option C is correct.

Hope this helps!

:)

A. x = 2

Step-by-step explanation:

(x+6)(x-1) ÷ (x-2)(x+6)

Since x+6 is common to both, numerator and denominator, it will get cancelled out

And there will be a hole at x = -6

The simplified form would be

(x-1)/(x-2)

There will be a vertical asymptote at x = 2, because the denominator becomes zero at x = 2

Explanation:

Remove Parenthesis: (a) = a

3x² + 4 - (-2x² + 3x + 6)

Simplify -(-2x² + 3x + 6): 2x² - 3x - 6

3x² + 4 + 2x² - 3x - 6

Simplify 3x² + 4 + 2x² - 3x - 6

5x² - 3x - 2

Apply Perfect Square Formula: (a - b)² = a² - 2ab + b²²: a = 2s, b = 7

(2s)² - 2 · 2s · 7 + 7²

Simplify (2s)² - 2 · 2s · 7 + 7²

4s² - 28s + 49

Remove Parenthesis: (a) = a

7y² + 9y - 2 - 3y² + 10

Group Like Terms

7y² - 3y² + 9y - 2 + 10

Add Similar Elements: 7y² - 3y² = 4y²

4y² + 9y - 2 + 10

Add: -2 + 10 = 8

4y² + 9y + 8