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Selen13
18.12.2019 •
Mathematics
Shear strength measurements for spot welds have been found to have standard deviation 1 0 pounds per square inch (psi). if 100 test welds are to be measured, what is the approximate probability that the sample mean will be within 1 psi of the true population mean.
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Ответ:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Let X the random variable that represent the Shear strength of a population, and for this case we know the distribution for X is given by:
Where
and ![\sigma=10](/tpl/images/0423/8788/09d96.png)
And let
represent the sample mean, the distribution for the sample mean is given by:
On this case![\bar X \sim N(\mu,\frac{10}{\sqrt{100}})](/tpl/images/0423/8788/aae88.png)
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability on this way:
And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.
Ответ:
same
Step-by-step explanation:
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