Show that the curve y = 2e^x + 3x + 5x^3 has no tangent line with slope 2. . so far, i've set it's derivative to now i'm tempted to take natural logs, but it doesn't seem to lead me anywhere

We are given with the equation y = 2e^x + 3x + 5x^3. the tangent line of the curve is determined through differentiation the equation. Hence the first derivative is expressed as y' = 2e^x + 3 + 15x^2. when y' or slope is 2, x can't be solved. Hence there is no tangent line with slope 2.

68688

Step-by-step explanation:

1) You add 16.3 + 7.65 + 4.5 to get 28.45%

2)You find 28.45% of 96,000 (27312)

3)You subtract 2,7312 from 96,000 to get 68688