hannahxmurphs
10.11.2020 •
Mathematics
Simplify: 4r3+2 - 6t2r3 + 3rt - 16
-2rt2 + 3rt - 16
4rt2 - 6t2r3 + 3rt - 16
r3t2 - 16
2r3+2 + 3rt - 16
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Ответ:
P(A)=1/7
P(B)=1/2
P(C)=1/42
P(A|C)=1/10
P(B|C)=1/10
P(A|B)=1/7
A and B are independent
A and C aren't independent
B and C aren't independent
Step-by-step explanation:
A="b falls in the middle"
- b can fall in seven possible places, but only one is the middle. So, P(A)=1/7
B="c falls to the right of b"
X=i means "b falls in the i-th position"
Y=j means "c falls in the j-th position"
if b falls in the first place, c can fall in the 2nd, 3rd, 4th, 5th, 6th or 7th place.
if b falls in the 2nd place, c can fall in the 3rd, 4th, 5th, 6th or 7th place
...
If b falls in the 6th place, c can fall in the 7th place
then:
" alt="P(B)=\displaystyle\sum_{i=1}^{6}( P(X=i)\displaystyle\sum_{j=i+1}^{7} P(Y=j))=\displaystyle\sum_{i=1}^{6}( \frac{1}{7}\displaystyle\sum_{j=i+1}^{7} \frac{1}{6})=\frac{1}{42}\displaystyle\sum_{i=1}^{6}(\displaystyle\sum_{j=i+1}^{7}1)=\frac{6+5+4+3+2+1}{42}=\frac{1}{2}" />" />
- if d falls in the 1st place, e falls in the 2nd and f in the 3rd place
- if d falls in the 2nd place, e falls in the 3rd and f in the 4th place
- if d falls in the 3rd place, e falls in the 4th and f in the 5th place
- if d falls in the 4th place, e falls in the 5th and f in the 6th place
- if d falls in the 5th place, e falls in the 6th and f in the 7th place
X=i means "d falls in the i-th position"
Y=j means "e falls in the j-th position"
Z=k means "f falls in the k-th position"
P(A|C)=P(A∩C)/P(C)=?
A∩C:
- d falls in the 1st place, e in the 2nd, f in the 3rd and b in the 4th place
- b falls in the 4th place, d in the 5th place, e in the 6th, f in the 7th place
P(A∩C)=2*(1/7*1/6*1/5*1/4)=1/420
P(A|C)=(1/420)/(1/42)=1/10
P(B|C)=P(B∩C)/P(C)=?
X=i means "d falls in the i-th position"
Y=j means "e falls in the j-th position"
Z=k means "f falls in the k-th position"
V=k means "b falls in the k-th position"
W=k means "c falls in the k-th position"
P(B|C)=(1/420)/(1/42)=1/10
P(A|B)=P(B∩A)/P(B)=?
B∩A:
- b falls in the 4th place and c in the 5th
- b falls in the 4th place and c in the 6th
- b falls in the 4th place and c in the 7th
P(B∩A)=3*(1/7*1/6)=1/14
P(A|B)=(1/14)(1/2)=1/7
If one event is independent of another, P(X∩Y)=P(X)P(Y)
So:
P(A∩B)=1/14=(1/7)*(1/2)=P(A)P(B), A and B are independent
P(A∩C)=1/420≠(1/7)*(1/42)=1/294=P(A)P(C), A and C aren't independent
P(B∩C)=1/420≠(1/2)*(1/42)=1/84=P(A)P(C), B and C aren't independent