Mathematics: Sin^2 x - 2 sin x = 0 find all solutions to the equation in the interval

Sin^2 x - 2 sin x = 0 find all solutions to the - id2203386984, bubblzthechicken

henrymototero

07.01.2022

Let $t=\sin(x)$ . The equation becomes

$t^2-2t=0 \iff t(t-2)=0$

So, the solutions are

$t=0,\quad t-2=0 \iff t=2$

Substitute back $t=\sin(x)$ , we have

$\sin(x)=0,\quad \sin(x)=2$

Since the sine function is bounded between -1 and 1, it can never equal 2. So, the only possible solution is

$\sin(x)=0 \iff x = k\pi,\quad k \in \mathbb{Z}$

Depending on the interval you're interested in (you didn't write it!) select the solution(s) that applies(apply)

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shoafmckenzie5263

15.12.2021

I DK what grade are you in

Explanation:

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