Slove the system of equations: y+4×=8and 5×+2y=13?

I am gonna use substitution method.
Solve for y in first equation,
y + 4x = 8
y = 8 -4x
Put the above y value in second equation,
5x + 2y = 13
5x + 2(8-4x) = 13
5x + 16 - 8x = 13
-3x = 13-16
-3x = -3
x = -3/-3
x = 1/1 = 1
Put the x value in first equation,
y + 4x = 8
y + 4(1) = 8
y = 8 - 4
y = 4
Hence, the solution is (1,4)

im pretty sure its false

Step-by-step explanation: