Sodium oxide (na2o) can react with hydrochloric acid (hcl) to produce sodium chloride (nacl) and water (h2o) according to the following equation: na2o + 2hcl -> 2nacl + h2o how many total atoms are present before and after the reaction

7 before and 7 after

Step-by-step explanation:

Before:

Na2O=3 atoms

2HCl=4 atoms

After:

2NaCl=4 atoms

H2O=3 atoms

Na2O + 2HCl -> 2NaCl + H2O then it wil be 10.3 atoms left in the cycle

Step-by-step explanation: you would take

(Na2O) then (HCl) then (NaCl) and, (H2O)

And you would got to the table of atoms and put them together if you look at the name of a chemical it show a number well you would divide them in to fractions and the denominator you would need to focus on because that is going to be your answer.  

A.) y = 12x, where y is the total money earned and x is the amount of days Bill worked. Bill earns 12 dollars per day, and after x days, he has y money. 
B.) b = 2s + 2, where b represents Bill and s represents Steve.