Mathematics: Solve: 12 Superscript x squared + 5 x minus 4 Baseline = 12 Superscript 2 x + 6

Solve: 12 Superscript x squared + 5 x minus 4

brooke7768

19.01.2022

x = - 5

x = 2

Step-by-step explanation:

We want to solve ;

${12}^{ {x}^{2} + 5x - 4} = {12}^{2x + 6}$

We equate the exponents, because is the same on both sides.

${x}^{2} + 5x - 4 = 2x + 6$

We group and rewrite in standard form to get:

${x}^{2} + 5x - 2x - 4 - 6 = 0$

${x}^{2} + 3x- 10= 0$

${x}^{2} - 2x + 5x - 10 = 0$

x(x - 2) + 5(x - 2) = 0

(x + 5)(x - 2) = 0

$x = - 5 \: or \: x = 2$

0,0(0 оценок)