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kleathers97
31.01.2020 •
Mathematics
Solve 2cos2x + cosx − 1 = 0 for x over the interval [0, 2pi ).
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Ответ:
2cos^2x+cosx-1 = 0
2cos^2x + 2cosx - cosx - 1 = 0
(2cos^2x + 2cosx) - (cosx + 1) = 02cosx(cosx + 1) - 1(cosx + 1) = 0
(cosx + 1)(2cosx - 1) = 0
cosx+1 = 0 or 2cosx-1 = 0cosx+1 = 0 gives cosx = -1, x = PI
2cosx-1 = 0 gives cosx = 1/2, x = PI/3 or x = 5PI/3
x = PI/3 or x = PI or x = 5PI/3Ответ:
which question are u talking about