Solve 3^(4x-5)=〖27〗^(x+10) for x. Show your work
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x =35

Step-by-step explanation:

3^(4x-5)=〖27〗^(x+10)

We need to get the same base

27 = 3^3

3^(4x-5)=3^3^(x+10)

We know a^b^c = a^(b*c)

3^(4x-5)=3^(3*(x+10))

Since the bases are the same, the exponents are equal

4x-5 = 3(x+10)

Distribute

4x-5 = 3x+30

Subtract 3x from each side

4x-3x-5 = 3x-3x+30

x-5 =30

Add 5 to each side

x-5+5 = 30+5

x = 35

d

Step-by-step explanation: