glogaming16

27.03.2020 •

Mathematics

Solve:
-5p + 18 = -6 -7p

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Ответ:

jonmorton159

01.11.2022

Mathematics

a. The two events are dependent.

b. $P(A\cap B)$ = $\frac{1}{220}$ .

Step-by-step explanation:

Given

Total coins =220

Number of Indian pennies= 6

A: When one of the 220 coins is randomly selected, it is one of the Indian pennies.

Therefore , the probability of getting an Indian pennies= $\frac{6}{220 }$

By using formula of probability= $\frac{Number \; of\; favourable\; cases}{total\; number \; of \;cases}$

Probability of getting an Indian pennies= $\frac{3}{110}$

B: When another one of the 220 coins is randomly selected( with replacement) , It is also one of the Indian pennies.

Therefore, probability of getting an Indian pennies= $\frac{6}{220}$

Probability of getting an Indian pennies = $\frac{3}{110}$

$A\cap B$ : 1

$P(A\cap B)=\frac{1}{220}$

If two events are independent. Then

$P(A\cap B)= P(A)\times p(B)$

P(A).P(B)= $\frac{3}{110} \times \frac{3}{110}$ = $\frac{9}{12100}$

Hence, $P(A\cap B)\neq P(A).P(B)$

Therefore, the two events are dependent.

b. Probability that events A and B both occur

Number of favourable cases when both events A and B occur=1

Total coins=220

Probability= $\frac{Number \; of\; favourable \; cases}{Total\; number\; of\; cases}$

$P(A\cap B)=\frac{1}{220}$

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Solve: -5p + 18 = -6 -7p