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annsmith66
24.07.2021 •
Mathematics
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Ответ:
Ответ:
Null hypothesis:![\mu_1 = \mu_2 = ..... \mu_j , j =1,2,....,n](/tpl/images/0661/2692/56288.png)
Alternative hypothesis:![\mu_i \neq \mu_j , i,j =1,2,....,n](/tpl/images/0661/2692/bc508.png)
The alternative hypothesis for this case is that at least one mean is different from the others.
And the best method for this case is an ANOVA test.
Step-by-step explanation:
For this case we wnat to test if all the mean length of all face-to-face meetings and the mean length of all Zoom meetings are the same. So then the system of hypothesis are:
Null hypothesis:![\mu_1 = \mu_2 = ..... \mu_j , j =1,2,....,n](/tpl/images/0661/2692/56288.png)
Alternative hypothesis:![\mu_i \neq \mu_j , i,j =1,2,....,n](/tpl/images/0661/2692/bc508.png)
The alternative hypothesis for this case is that at least one mean is different from the others.
And the best method for this case is an ANOVA test.