Solve each component inequality and graph the - id632002, maribelarreolap4sgpj

Ответ:

dbhuggybearow6jng

12.03.2022

Mathematics

Solution: The value of x after solving both components is or (2,11] .

Explanation:

From the first component it is clearly noticed that the value of x is greater than 2.

Simplify the second component.

$x-1\leq 10\\x\leq 11$

From the above inequality it is clearly noticed that the value of x is less than or equal to 11.

Solving both components we get and the graphical representation is shown in the figure.

The red portion shows the solutions of , blue portion shows the solution of $x-1\leq 10$ and purple portion which combination of red and blue portion shows the solution of both inequalities.

Therefore, value of x after solving both components is or (2,11] .

$Solve each component inequality and graph the solution[tex]x > 2 and \: x - 1 \leqslant 10[/tex$

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Ответ:

trint4

05.01.2023

Mathematics

$\huge \boxed{\mathfrak{Question} \downarrow}$

8x cube minus 27y cube divided by 2x minus 3y.

$\large \boxed{\mathbb{ANSWER \: WITH \: EXPLANATION} \downarrow}$

$\sf\frac { 8 x ^ { 3 } - 27 y ^ { 3 } } { 2 x - 3 y } \\$

Factor the expressions that are not already factored.

How to factorise :-

Rewrite $\sf8x^{3}-27y^{3}$ as $\sf\left(2x\right)^{3}-\left(3y\right)^{3}$ . The difference of cubes can be factored using the algebraic rule: $\sf\:a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right)$ .

$\rightarrow \sf \: \frac{\left(2x-3y\right)\left(4x^{2}+6xy+9y^{2}\right)}{2x-3y} \\$

Cancel out 2x-3y in both the numerator and denominator.

$\boxed{ \boxed{ \bf \: 4x^{2}+6xy+9y^{2} }}$

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Solve each component inequality and graph the solution $x > 2 and \: x - 1 \leqslant 10$

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