Mathematics: SOLVE FASTTT The base of a triangle is 9 cm correct to the nearest om The area of this triangle is 40 cm correct to the nearest 5 Calculate the upper bound for the perpendicular height of this triangle

SOLVE FASTTT The base of a triangle is 9 cm correct

rebeccathecatt

20.09.2021

Step-by-step explanation:

Area of triangle is 40 cm² correct to nearest 5cm² .

∴ Area of triangle = ( 40 ± 5) cm²

∴ upper bound for area of triangle is = (40 + 5) cm² = 45cm²

Base of triangle = 9cm

∵ area of triangle = 1/2 base × height

height = 2 × area of triangle/base

∴ upper bound for height of triangle = 2 × upper bound area/base

= 2 × 45/9 = 10cm

Hence answer is 10cm

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NateTheBeast12

02.11.2020

area of base = $\pi r^2$

where 'r' is the radius

Step-by-step explanation:

Volume of the cylinder formula = $\pi r^2h$

volume of cylinder = area of base * height

The base of a cylinder is a circle. so we use the area of circle for the base of cylinder while finding volume

We know area of the circle is $\pi r^2$

So area of the base of cylinder is $\pi r^2$

To find volume of the cylinder , we multiply the base of the cylinder with height

To determine the base of the cylinder we need radius of the cylinder

area of base = $\pi r^2$

where 'r' is the radius

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