Solve for the given length. the length of a rectangle is 3m longer than its width. the area of the rectangle is 154^2. what is the width of the rectangle? show all work

By definition the area of a rectangle is given by:
 A = (w) * (l)
 Where,
 w: width
 l: long
 We rewrite the expression based on:
 "The length of a rectangle is 3m longer than its width"
 A = (w) * (w + 3)
 We substitute the value of the area:
 154 ^ 2 = (w) * (w + 3)
 Rewrite:
 23716 = w ^ 2 + 3w
 w ^ 2 + 3w-23716 = 0
 We solve the polynomial:
 w = 152.5
 Note: the other root is negative.
  
 the width of the rectangle is: 
 w = 152.5 m

If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m

The answer is
D. power of a power

 
x^⁴)⁹ = (x^4*9)= x^36