vickygloom
06.01.2020 •
Mathematics
Solve for x. −ax 3b > 5 x > the quantity 3 times b minus 5 all over a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over a x < the quantity negative 3 times b plus 5 all over negative a
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Ответ:
Subtract 3b: -ax > 5 -3b
Diuvide by - a, which implies to change the sign > to <:
x < [5 -3b]/ (-a) or x < [3b - 5]/a both are equivalent
That is second option.
Ответ:
Just messing with you but:
3 + ∞ = 5 + ∞