Mathematics: Solve for x in the equation x² -8x + 41 = 0

Solve for x in the equation x² -8x + 41 = 0 - id8410145503, michelemosbahiow6yya

amandajbrewerdavis

10.03.2022

x=4+5i and x=4-5i

Step-by-step explanation:

x^2-8x + 41 = 0

we apply quadratic formula to solve for x

$x=\frac{-b+-\sqrt{b^2-4ac}}{2a}$

a= 1, b= -8 and c= 41

Plug in all the values in the formula

$x=\frac{-b+-\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-8)+-\sqrt{(-8)^2-4(1)(41)}}{2(1)}$

$x=\frac{8+-\sqrt{64-164}}{2}$

$x=\frac{8+-\sqrt{-100}}{2}$

square root (-1) is 'i'

$x=\frac{8+-10i}{2}$

Divide both terms by 2

x= 4+-5i

two values of x are 4+5i and 4-5i

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jhjhgjvygv

23.02.2022

2x+3y=-6

x-y=5

Step-by-step explanation:

just finished the lesson these are the answers

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