Solve for x. Leave your answer in simplest radical form.

2√5

Step-by-step explanation:

hypotenuse of the second triangle = √(9²-5²)

= 2√14

so,

x = √{(2√14)²-6²}

= 2√5

2sqrt(5)

Step-by-step explanation:

The left triangle is a right triangle so we can use the Pythagorean theorem

a^2+b^2 = c^2 where a and b are the legs  and c is the hypotenuse

5^2 + b^2 = 9^2

b^2 = 9^2 - 5^2

b^2 = 81-25

b^2 =56

Taking the square root of each side

b = sqrt(56) = sqrt(4*14) = 2 sqrt(14)

The right side is also a right triangle so we can  use the Pythagorean theorem

a^2+b^2 = c^2 where a and b are the legs  and c is the hypotenuse

x^2 + 6^2 = (sqrt(56))^2

x^2 +36 = 56

x^2 = 56-36

x^2 = 20

Taking the square root

sqrt(x^2) = sqrt(20) = sqrt(4*5) = 2sqrt(5)

B en edg

Step-by-step explanation: