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sosa71
09.01.2021 •
Mathematics
Solve the equation 8 sin x = 2.5 for
the interval 0° to 720°
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Ответ:
18.2°, 161.8° and 378.2°
Step-by-step explanation:
Given the expression:
8 sin x = 2.5
Divide both sides by 8
sinx = 2.5/8
Sinx = 0.3125
x = arcsin(0.3125)
x1 = 18.2
Since sin theta is positive in the second quadrant, x2 = 180 - 18.2 = 161.8°
Since our angle must lie in between 0° and 720°,then;
x3 = 360 + 18.2 = 378.2°
Hence the required angles are 18.2°, 161.8° and 378.2°
Ответ:
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Step-by-step explanation: