Mathematics: Solve the equation algebraically. 9^x-2 = (1/27)^x+4

Hey There!Let s solve....We know that...Angle BCA=70°I hope it is helpful....Cheers!________...

Solve the equation algebraically. 9^x-2 = (1/27)^x+4

Ответ:

puppystar159p51vxk

01.01.2022

(3^2)^x-2 = (1/3^3)^x+4
3^2 ^(x-2) = (3^-3)^x+4
3^2x-4 = 3^-3(x+4)
3^2x-4 = 3^-3x-12
2x-4 = -3x-12
x= - 8/5
x= -1 3/4 , x= -1.6

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Ответ:

deidaralove90

26.09.2022

Mathematics

Hey There!

Let's solve....

$\angle \: ab = bc \\ so \: it \: is \: given \: that \: \\ \angle \: bac = 40 ^{ \degree} \\ \\ so \: \angle \: abc + \angle \: bca \: + \angle \: bac \\ = 180 \\$

We know that...

$\angle \: abc = \angle \: bca \\ so \: it \: is \: \frac{180 - 40}{2} \\ \\ = \frac{ \cancel{140}^{70} }{ \cancel{2}} \\ \\ = 70 \degree$

Angle BCA=70°

$\angle \: acd + \angle \: acb = 180 \degree \\ \therefore \angle \: acd = 180 - 70 \\ = 110 \degree \\$

I hope it is helpful....Cheers!________
ABC is an isosceles triangle,AB=AC an angle BAC = 40⁰ Calculate the other two angles of the triangle

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Solve the equation algebraically. 9^x-2 = (1/27)^x+4

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