Solve the equation for all values of x.
(22 – 16)(2x2 + 49) = 0
Help please

7i/sqrt(2)

Step-by-step explanation:

so, if I understand correctly, the equation is

(22-16)(2x² + 49) = 0

6(2x² + 49) = 0

that automatically means

2x² + 49 = 0

2x² = -49

x² = -49/2

x = sqrt(-49/2)

a square root of a negative number has no real solution. the solution is in the world of complex and imaginary numbers, which bases on the sqrt(-1) = i.

so, we get

x = sqrt(49/2 × -1) = (7/sqrt(2)) × I = 7i/sqrt(2)