Mathematics: Solve the equation on the interval [0, 2π). cos x + 2 cos x sin x = 0 a. pi/2, 7pi/6, 3pi/2 b. pi/2, 7pi/6, 3pi/2, 11pi/6 c. 7pi/6, 11pi/6 2π

Solve the equation on the interval [0, 2π). cos

Ответ:

cherbears

17.01.2022

$\cos x+2\cos x\sin x=\cos x(1+2\sin x)=0$

$\cos x=0$ in the given interval when $x=\dfrac\pi2,\dfrac{3\pi}2$ .

$1+2\sin x=0\implies \sin x=-\dfrac12$ when $x=\dfrac{7\pi}6,\dfrac{11\pi}6$ .

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Ответ:

AT3P

08.05.2023

Mathematics

i need help

Step-by-step explanation:

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Solve the equation on the interval [0, 2π).

cos x + 2 cos x sin x = 0
a. pi/2, 7pi/6, 3pi/2

b. pi/2, 7pi/6, 3pi/2, 11pi/6

c. 7pi/6, 11pi/6 2π

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