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shemarmcdonald4662
28.10.2019 •
Mathematics
Solve the following system.
y= + 2x - 1 and 3x - y=1
the solutions are _and_
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Ответ:
Since the coefficient of the quadratic variable is missing, I obtained it from a similar question.
The system is:
y = (1/2)x² + 2²x - 1 and 3x - y = 1The two solutions are (0, -1) and (2, 5)Explanation:
1. Write the system
2. Clear y from the second equation to solve by substitution
3. Substitute in the first equation and solve for x
4. Subsitute both values into the equation y= 3x - 1
y = 3(0) - 1 = - 1 ⇒ solution (0, -1)y = 3(2) - 1 = 5 ⇒ solution (2, 5)Ответ:
A
Step-by-step explanation: