Solve the following triangles. Round the lengths of sides to the nearest tenth and angle measures to the nearest degree. Use the "Law of cosines" and "law of sines" A=46°, B=4in, C=8in

a = 10

d = 5

Step-by-step explanation:

a + 4d = 30 ------------------(I)

a + 12d =70 -------------(II)

Multiply equation (II) by (-1) and then add.So, 'a' will be eliminated and you can find the value of d

(I)         a +   4d = 30

(II)*(-1)   -a - 12d = -70   {Now add}

               - 8d   =  - 40

Divide both sides by (-8)

d = -40/-8

d = 5

Plugin d = 5 in equation (I)

a + 4*5 = 30

a + 20 = 30

a = 30 - 20

a = 10