Solve the inequality for x. –8x + 16 > –72 A) x 7 D) x > 11

x < 11

Step-by-step explanation:

–8x + 16 > –72

Let's transfer the components which do not contain x to the right side and change sign of these components

-8x > -72 - 16

Now, we simplify the right side

-8x > -88

We then multiply both sides by (-1/8) and change the greater symbol to smaller symbol

(-1/8)*(-8)x < (-1/8)*(-88)

Finally, we simplify both sides to solve this inequality

x < 11

Hope this helps!

Airplane #1 equation: y=5/13x+42/13

Airplane #2 equation: y=1/3x+14

Step-by-step explanation:

So to find the slope of each airplane, you use the formula y2-y1/x2-x1. That means, for airplane#1 the equation will be 9-4/15-2. Simplify this and get 5/13. Then, for airplane#2, the equation will be 12-9/6-15. Simplify this and get 3/-9 and divide each side by 3 to get 1/-3 or -1/3. Next, use point slope formula to find the system of linear equations. Point slope formula is y-y1=m(x-x1). M is the slope. Use any point from the line. In this case, I will use (2,4). Tat means the first airplane's equation would be y-4=5/13(x-2). Then y-4=5/13x-10/13. Then, convert four into a fraction with a denominator of 13. This means, you have to multiply 4 by 13 to get 52/13. Add 52/13 to -10/13 to get 42/13. That means the first equation will be y=5/13x+42/13. The second equation point will be (6,12). This means the equation will be y-12=-1/3(x-6). Simplify this to get y-12=-1/3x+2. Simplify this to get y=1/3x+14. Therefore, Airplane#1 equation will be y=5/13x+42/13 and airplane #2 equation will be  y=1/3x+14.

Hope this helps