Solve the linear programming problem by the method of corners. Maximize P = 6x − 4y subject to x + 2y ≤ 50 5x + 4y ≤ 145 2x + y ≥ 25 y ≥ 7, x ≥ 0 The maximum is P = 1 Incorrect: Your answer is incorrect. at (x, y) = .

The maximum is P=112.4 at (23.4,7)

Step-by-step explanation:

From the graph, the coordinates of the vertices of the feasible region are:

(0,25)

(9,7)

(23.4, 7)

(15,17.5)

Substituting these values in the objective function, P.

At (0,25), P = 6x − 4y=6(0)-4(25)=-100

At (9,7), P = 6x − 4y=6(9)-4(7)=26

At (23.4,7), P = 6x − 4y=6(23.4)-4(7)=112.4

At (15,17.5), P = 6x − 4y=6(15)-4(17.5)=20

Since the objective is to maximize,

The maximum is P=112.4 at (23.4,7)

The answer is B

Step-by-step explanation:

Hope this helps :))