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tinamarie04ts
10.03.2020 •
Mathematics
Solve the system by finding the reduced row-echelon form of the augmented matrix.
x-4y-2z=2
2x-11y-10z=13
-x+6y+6z=-8
If there is one solution, give its coordinates in the answer spaces below. If there are infinitely many solutions, enter t in the answer blank for z, enter a formula for yy in terms of tt in the answer blank for y and enter a formula for x in terms of tt in the answer blank for x. If there are no solutions, leave the answer blanks for x, y and z empty.
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Ответ:
Therefore the solution are
x=-6t-10
y=-3-2t
z=t
Step-by-step explanation:
Given system of the equation is
x-4y -2z=2
2x-11y-10z=13
-x+6y+6z=-8
Transforming matrix of the reduce row echelon form
add -2 times the first row to the second row
add 1 times the row to the third row
multiply the second row by![-\frac{1}{3}](/tpl/images/0540/0971/97cb1.png)
add -2 times the second row to the third row
add 4 times the second row to the first row
The reduce form of the system of equation is
x+0.y+6.z=-10......(1)
0.x+y+2z=-3.........(2)
There are infinity of many solution
z= t (say)
Putting the value of z in the equations of (1) and (2)
x +6t=-10
⇒x=-6t-10
and
y+2t=-3
⇒y= -3-2t
Therefore the solution are
x=-6t-10
y=-3-2t
z=t
Ответ:
Need more info before I can answer this
Step-by-step explanation: