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harleyandpope90
26.07.2019 •
Mathematics
Solve the system of equations.
2x + 2y + 3z = 5
6x + 3y + ôz = 6
3x + 4y + 4z = 9
a. (x = 0, y = 1, z = 0)
b. (x = 1, y = 0, z = 3)
c. (x = -2, y = 3, 2 = 2)
d. (x=-1, y = 2,2 = 1)
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Ответ:
x=-1, y = 2, z = 1
Step-by-step explanation:
We are given with three equations and we are asked to find the solution to them.
2x + 2y + 3z = 5 (A)
6x + 3y + 6z = 6 (B)
3x + 4y + 4z = 9 (C)
Step 1 .
multiplying equation (A) by 3 and subtracting B from the result
6x + 6y + 9z = 15
6x + 3y + 6z = 6
- - - = -
3y+3z=9
y+z=3
y=3-z (C)
Step 2.
Substituting this value of y in equation B and C
6x + 3(3-z) + 6z = 6
6x+9-3z+6z=6
6x+3z=-3
2x+z=-1 (D)
3x + 4(3-z) + 4z = 9
3x+12-4z+4z=9
3x=-3
x=-1 (E)
Putting this value f x in (D)
2(-1)+z=-1
-2+z=-1
z=1
Now we put this value of z in equation (C)
y=3-z
y=3-1
y=2
Hence we have
x=-1, y=2 and z=1
Ответ: