Solve the system of equations.
3x – 4y = 25
3x + 2y = 1
A. (1, -1)
B. (3,-4)
C. (-3,-9)
D. (7,-1)

B

x = 3 and y = -4

Step-by-step explanation:

to solve this simultaneous equation  we adopt the substitution method

we say that let

3x – 4y = 25

equation 1

3x + 2y = 1 equation 2

from equation 2

3x + 2y = 1 equation 2

3x = 1-2y

divie both sides by 3

3x/3 = (1-2y)/3

x =  (1-2y)/3 equation 3

put x = ( 1- 2y)/3  into equation 1

3x – 4y = 25 equation 1

3( 1 -2y)/3 - 4y = 25

1-2y - 4y = 25

1 -6y =25

-6y =25 -1

-6y = 24

divide both sides by the coefficient of y which is -6

-6y/-6 = 24/-6

y = -4

put the value of y = -4 into equation 3

x =  (1-2y)/3 equation 3

x = ( 1- 2(-4)/ 3

x = 1 +8 /3

x = 9/3

x = 3

therefore the value of x = 3 and y = -4 respectively