Solve the system of equations. −9y+4x−20=0−7y+16x−80=0\begin{aligned} & -9y+4x - 20=0 & -7y+16x-80=0 \end{aligned} −9y+4x−20=0 −7y+16x−80=0 what is the value of x and y

(x, y) = (5, 0)

Step-by-step explanation:

Subtract 4 times the first equation from the second:

  (-7y +16x -80) -4(-9y +4x -20) = (0) -4(0)

  29y = 0 . . . . . simplify

  y = 0 . . . . . . . .divide by 29

  4x -20 = 0 . . . . substitute 0 for y in the first equation

  x -5 = 0 . . . . . .divide by 4

  x = 5 . . . . . . . . add 5

The solution to this system is (x, y) = (5, 0).

Well you are missing one side of the triangle from each.  In the first one you are missing the side AC and the second one you are missing the side DF.  So to prove that they are congruent by SSS you need that AC is congruent to DF