Solve with the substitution method
-6x+4=33
5x+18y=29

You have to solve for  1 variable
I'm pretty sure they want 4y and not just y becaseu taht is too easy

-6x+4y=33
5x+18y=29

solve for 1 variable

may be messy
-6x+4y=33
add 6x both sides
4y=33+6x
divide both sides by 4
y=(33+6x)/4
sub that for y in other equation

5x+18((33+6x)/4)=29
5x+9(33+6x)/2=29
5x+(297+54x)/2=29
(10x/2)+(297+54x)/2=29
times both sides by 2
10x+297+54x=58
297+64x=58
minus 297 both sides
64x=-239
divide both sides by 64
x=-239/64
sub back

y=(33+6x)/4
y=(33+6(-239/64))/4
y=(33-717/32)/4
y=(1056/32-717/32)/4
y=(339/32)/4
y=339/128

the solution is

you can graph it and check if you want

'Rectangle formed by ordered pairs A at negative 4, 2, B at negative 4, 1, C at negative 1, 1, D at negative 1, 2. Second rectangle formed by ordered pairs A double prime at 4, negative 2, B double prime at 4, negative 1, C double prime at 1, negative 1, D double prime at 1, negative 2.
Reflected over the x‒axis and reflected over the y-axis