Solve (x + 3)2 + (x + 3) – 2 = 0. let u = rewrite the equation in terms of u. (u2 + 3) + u – 2 = 0 u2 + u – 2 = 0 (u2 + 9) + u – 2 = 0 u2 + u + 1 = 0 factor the equation. what are the solutions of the original equation?

The solutions of the original equation are x=-5 and x=-2

Step-by-step explanation:

we have

Let

Rewrite the equation

Complete  the square

rewrite as perfect squares

square root both sides

the solutions are

u=-2,u=1

Alternative Method

The formula to solve a quadratic equation of the form

is equal to

in this problem we have

so

substitute in the formula

the solutions are

u=-2,u=1

Find the solutions of  the original equation

For u=-2

---->

For u=1

---->

therefore

The solutions of the original equation are

x=-5 and x=-2

Responder:

x = 15/7

Explicação passo a passo:

Dada a equação:

7 x + 4 = 19

Subtraia 4 de ambos os lados

7x + 4 - 4 = 19 - 4

7x = 15

Divida os dois lados por 7

7x / 7 = 15/7

x = 15/7