Mathematics: Solve (x + 3)^2 + (x + 3) – 2 = 0. let u = x+3 rewrite the equation in terms of u. a. u^2 + u – 2 = 0 b. (u^2 + 9) + u – 2 = 0 c. u^2 + u + 1 = 0

Solve (x + 3)^2 + (x + 3) – 2 = 0. let u = x+3

starbae1084

05.01.2022

The answer is the option A

$u^{2}+u-2=0$

Step-by-step explanation:

we have

$(x+3)^{2}+(x+3)-2=0$

Let

u=(x+3)

Substitute

$(u)^{2}+(u)-2=0$

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normarismendoza

27.01.2022

I cant answer rn but I will get back to you shortly -

Step-by-step explanation:

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