Solve x2 + 2x + 9 = 0. (2 points) =
O x=-2+41/2
O x=-2 +21/2
x=
O x=-1+ 41/2
x =
O
x=-1+2iv 2

The question is asking how many ways can ten team be randomly assigned to 5 games. They can be randomly assigned in nPrC 
r = n!/( n-r)! ways. 
 So we have that 10 teams can be randomly assigned to five games in 10C5 ways. 
 10C5 = 10!/ (10-5)! = 10!/ 5! = 30240 ways. So they can be arranged in 30240 ways.