smokemicpot
06.06.2020 •
Mathematics
Square OABC is drawn on a centimetre grid. O is(0,0) A is(3,0) B is(3,3) C is(0,3). Write down how many invariant points there are on the perimeter of the square, when OABC is enlarged, scale factor 2, centre (0,0)
Solved
Show answers
More tips
- H Health and Medicine How Did Inna Lose Weight on Dom 2?...
- H Health and Medicine Coughing: Causes, Types, and Treatment Methods...
- H Health and Medicine How to Treat the Flu: A Comprehensive Guide...
- O Other What is a Disk Emulsifier and How Does it Work?...
- F Family and Home What does a newborn need?...
- F Family and Home Choosing the Right Car Seat for Your Child: Tips and Recommendations...
- F Food and Cooking How to Get Reconfirmation of Registration?...
- C Computers and Internet How to Get Rid of Spam in ICQ?...
- A Art and Culture Who Said The Less We Love a Woman, the More She Likes Us ?...
- F Family and Home How to Get Rid of Your Neighbors?...
Answers on questions: Mathematics
- M Mathematics The price of a share of stock for company XYZ at the beginning of the week was $23.99. Over the next five days, the share of stock gained $3.60 on Monday, lost $4.51 on Tuesday,...
- M Mathematics Elisha wants to attend the town carnival. the price of the admission to the carnival is $5.50, and each ride costs an additional 88 cents. if he can spend at most $26.00 at the carnival,...
- H Health The us health system does lead in the world in which area...
- H History The taj mahal is an example of architecture for which example a) inca b) mongol c) mughal d) roman...
Ответ:
1 point. O (0,0)
Step-by-step explanation:
Hi
Invariant points are those points who remain on the same location after a given transformation.
1. Plotting OABC we have it below:
2. Whenever we dilate centered, the image O'A'B'C' will be determined by the following points:
Since the Scale factor is (2)
3. Check it out O'A'B'C' below
4. On the perimeter of O'A'B'C' (enlarged OABC) we have left 1 point invariant.
Ответ:
Step-by-step explanation:
There are 30 teachers for the principal to choose from initially. After the principal chooses one, there will be 29, 28, 27, and so on.
Since the principal is only choosing 3, there are permutations. However, the order of which the principal chooses the teachers does not matter. In other words, without loss of generality, let the name of three of the teachers be Adam, Bernie, and Carla. Regardless of whether the principal chooses Adam then Bernie then Carla or Carla then Adam then Bernie, etcetera, the same three teachers are still being chosen.
Thus, we must divide by the number of ways you can rearrange three distinct teachers, which is .
Therefore, the desired answer is