anishivaturi123
26.10.2019 •
Mathematics
Statistics question:
distances are normally distributed and have a standard deviation of 43 yards. if a 350 yard drive puts an individual in the top 1% of all drives, what is the mean of this distribution?
so we're trying to find the mean of this distribution given the standard deviation and a percentage. i'm having trouble figuring what method to do to get this and would appreciate a thorough explanation. will give !
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Ответ:
■
a = 141°
b = 13°
c = 26°
■ Step-by-step explanation:
a = 128 + b
c = 2b
a + b + c = 128
replace a & c
(128 + b) + b + 2b = 180
4b = 180 - 128
4b = 52
b = 13°
a = 128° + 13° = 141°
c = 2×13° = 26°