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Ответ:

mel2001love

03.02.2020

Mathematics

Step-by-step explanation:

dy/dt=(y+1)(2√t)

separate the variables and integrating

$\int \frac{dy}{y+1} =\int\ {2\sqrt{t} } \, dt \\log(y+1)=2\frac{t^{\frac{3}{2} } }{\frac{3}{2} } +c\\y+1=e^{\frac{4}{3}t^{\frac{3}{2}+c } } =Ce^{t^{\frac{3}{2} }} \\y=Ce^{t^{\frac{3}{2} } } -1$

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