Stephen kicked a ball inside. The equation that represents the height h in feet of the ball after being kicked and elapsed amount of time t in seconds

The maximum height of the ball is: 14.0625ft

Step-by-step explanation:

The missing information is:

Required

The maximum height the ball attained

First, we calculate the time to reach the maximum height.

For a function:

The maximum is:

So, the maximum of is:

Where

So:

The maximum height is then calculated as:

The comparisons are as follows:

Extremes:

Let the upper box plot be for class 1 and the second one be for class 2

The lowest value in class 1 is 53 and for class 2 is 56 while the highest value for class 1 is 89 and for class 2 is 96.

Ranges:

The range for class 1 is: 89-53 = 36

The range for class 2 is: 96-56 = 40

Class 2 has a range larger than class 1

Quartiles:

For class 1:

First quartile: 62

Third quartile: 86

IQR: 86-62 = 24

For class 2:

First quartile: 62

Third quartile: 89

IQR: 86-62 = 27

The IQR for class 2 is larger than IQR of class 1.

Medians:

The median for class one is: 80 and for class 2 is 74

Hence we can conclude that the scores of class 2 are more spread than the scores of class 1 ..