Store A sells lawnmower fuel for $4.00 per gallon.

Store B sells containers of fuel for $4.00 each.

The cost of fuel at either store can be modeled by the function
c
(
n
) = 4
n
, where
n
is the number of gallons of fuel for Store A and
n
is the number of containers of fuel at Store B.

The domain of
c
(
n
) = 4
n
is all real numbers.

For each store, drag all the additional restrictions needed on values of
n
for
c
(
n
) to model each situation.

Solved

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Ответ:

aj0914

21.03.2022

Mathematics

Step-by-step explanation:

Let's start by rewriting the second equation in terms of "x":

x+y=5

Subtract y from both sides:

x=5-y

Now, substitute "5-y" for "x" in the first equation:

(5-y)^2-y^2=100

Note that:

(a-b)^2=a^2-2ab+b^2

25-10y+y^2-y^2=100

Cancel out like terms:

25-10y=100

Subtract 25 from both sides:

-10y=75

Divide both sides by -10

$y=\frac{75}{-10}=\frac{15}{-2}=-\frac{15}{2}$

Now, substitute this value back into either of the equations to solve for x.

$x+y=5\\x-\frac{15}{2}=5\\$

Add 15/2 to both sides:

$x=5+\frac{15}{2}\\x=\frac{10}{2}+\frac{15}{2}\\x=\frac{25}{2}$

Now, find the difference:

$x-y=\frac{25}{2}-(-\frac{15}{2})=\frac{25}{2}+\frac{15}{2}=\frac{40}{2}=20$

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