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realneggalloyd
30.11.2019 •
Mathematics
Super easy word problem with question : (
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Ответ:
1. The required slope m, for the context is![m = 1.08](/tpl/images/0397/1965/c2459.png)
2. The y-intercept in the context is![a = y = 1052](/tpl/images/0397/1965/ab84c.png)
3. The graph is on Desmos.
Step-by-step explanation:
Given:
Where,
a is the speed of sound wave.
t is the air temperature.
This is a linear model type equation.
Can be represented in the slope intercept form which is equal to
Where,
m = Slope of the line.
c = y-intercept.
Now if we compare the given model by slope intercept formula we get
So ,the slope in the context of the problem is
.
and the y intercept in the context of the problem![a = c = y = 1052](/tpl/images/0397/1965/29611.png)
For Sketching the graph we require two point
put t = 0
∴ a = 1052
Let A (1052, 0) be one point.
put a = 0
∴ t = -974.07
Let B (0, -974.07) another point.
So, the x intercept of the linear model is![t = x = -974.07](/tpl/images/0397/1965/bbf5f.png)
Here in the graph
X axis represent temperature in degree, Fahrenheit.(t)
Y axis represent Speed of sound wave in feet per second.(a)
Scale on both axes:
1 cm = 100 feet per second on y-axis
1 cm = 100 degree Fahrenheit on x-axis
Ответ:
The points option A) (4,-5) and option C) (2,1) lies on the line m.
Step-by-step explanation:
The given equation of the line is![y = (-2/3)x + 8](/tpl/images/0561/3836/7af82.png)
The general equation of the line is![y=mx+b](/tpl/images/0561/3836/904ac.png)
where,
m is the slope of the line.b is the y-intercept of the line.From the given equation,
It can be found that the slope of the line, m is -2/3.
The line is parallel to the given line. Therefore, their slopes are equal.
Since the two lines are parallel, their slope is also same.
The line passes through the point (-1,3).
To find the slope :
Slope =![(y2-y1)/(x2-x1)](/tpl/images/0561/3836/b238a.png)
Now, let's check the each options to find the slope is same or not.
Option A) is (-4,5) and the given point is (-1,3)
Slope =![(3-5)/(-1+4)](/tpl/images/0561/3836/2ec5b.png)
⇒ slope = -2/3
Therefore, the point (-4,5) could also be on the line m.
Option B) is (-3,6) and the given point is (-1,3)
Slope =![(3-6)/(-1+3)](/tpl/images/0561/3836/37f1d.png)
⇒ slope = -3/2
The point (-3,6) cannot be on the line m.
Option C) is (2,1) and the given point is (-1,3)
Slope =![(3-1)/(-1-2)](/tpl/images/0561/3836/145f6.png)
⇒ slope = -2/3
Therefore, the point (2,1) could also be on the line m.
Option D) is (3,-2) and the given point is (-1,3)
Slope =![(3+2)/(-1-3)](/tpl/images/0561/3836/9baa6.png)
⇒ slope = -5/4
The point (3,-2) cannot be on the line m.
Option E) is (6,-3) and the given point is (-1,3)
Slope =![(3+3)/(-1-6)](/tpl/images/0561/3836/77e6a.png)
⇒ slope = -6/7
The point (6,-3) cannot be on the line m.