Suppose a laboratory has a 38 g sample of polonium-210. the half-life of polonium-210 is about 138 days. how many half-lives of polonium-210 occur in 1104 days? how much polonium is in the sample 1104 days later? 9 ; 0.07 g 8 ; 2,2622 g 8 ; 4.75 g 8 ; 0.15 g

To find the number of half lives divide the total number of days by the number of days for 1 half live:

1104 / 138 = 8

There are 8 half lives.

To find the total amount left multiply the starting amount by 1/2 to the 8th power:

38 * 0.5^8 = 0.148 = 0.15 grams

The answer is the last one.

D. 8; 0.15 g

Step-by-step explanation:

We have been given that a a laboratory has a 38 g sample of polonium-210. The half-life of polonium-210 is about 138 days.

To find the half-lives of polonium-210, we will divide 1104 by 138.

Therefore, there are 8 half-lives will occur in 1104 days.

Therefore, 0.15 gm of the polonium will be left after 1104 days.

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Step-by-step explanation: