KillerSteamcar
31.07.2019 •
Mathematics
Suppose a new car that cost 20 000 depreciates by 15% each year. in how many year till the car costs 7500. use the equation 7500=(20,000)(0.85)^x
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Ответ:
3 = 8 * (0.85)^x => 0.85^x = 3/8
next, we can take the log() on both sides, and use the fact that log(a^b)=b*log(a)
log(3/8) = log(0.85^x) => log(3/8) / log(0.85) = x
If you calculate this, you find x ≈ 6.03
Ответ: