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hwk4102
02.12.2021 •
Mathematics
Suppose a normal distribution has a mean of 62 and a standard deviation of
4. What is the probability that a data value is between 59 and 67? Round your
answer to the nearest tenth of a percent.
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Ответ:
66.8% or 0.66772
Step-by-step explanation:
0.66772
Given that :
Mean (m) = 62
Standard deviation (s) = 4
probability that a data value is between 57 and 65
P(57 < x < 65)
Using the relation :
(x - m) / s
P(x < 57) :
(57 - 62) / 4 = - 1.25
P(Z < - 1.25) = 0.10565 ( Z probability calculator)
P(x < 65) :
(65 - 62) / 4 = 0.75
P(Z < 0.75) = 0.77337 (Z probability calculator)
P(Z < 0.75) - P(Z < - 1.25)
0.77337 - 0.10565 = 0.66772
Ответ:
hope it helps
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